I found char array can be initialized by string literal ! Is such coding correct?

--------------------------------------
int main() {
char tnam[]="tmpnamXXXXXX";

int fd=::mkstemp(tnam);
return 0;
}

g++ t.cpp -std=gnu++11

On Thursday, 27 July 2023 at 14:51:57 UTC+1, wij wrote:
> I found char array can be initialized by string literal ! Is such coding correct?
>
> --------------------------------------
> int main() {
> char tnam[]="tmpnamXXXXXX";
>
> int fd=::mkstemp(tnam);
> return 0;
> }
>
> g++ t.cpp -std=gnu++11
>
Yes, that's fine.
char modifable[] = "This string can be modiifed";
const char *constant = "This string shouldn't be modified";

On Thursday, 27 July 2023 at 14:51:57 UTC+1, wij wrote:
> I found char array can be initialized by string literal ! Is such coding correct?
>
> --------------------------------------
> int main() {
> char tnam[]="tmpnamXXXXXX";
>
> int fd=::mkstemp(tnam);
> return 0;
> }
>
> g++ t.cpp -std=gnu++11

N3096: 6.7.10 Initialization

15 - An array of character type may be initialized by a character string
literalor UTF-8 string literal, optionally enclosed in braces.
Successive bytes of the string literal (including the terminating null
character if there is room or if the array is of unknown size) initialize
the elements of the array.

On 2023-07-27 4:14 PM, Tony Oliver wrote:
> On Thursday, 27 July 2023 at 14:51:57 UTC+1, wij wrote:
>> I found char array can be initialized by string literal ! Is such coding correct?
>>
>> --------------------------------------
>> int main() {
>> char tnam[]="tmpnamXXXXXX";
>>
>> int fd=::mkstemp(tnam);
>> return 0;
>> }
>>
>> g++ t.cpp -std=gnu++11
>
> N3096: 6.7.10 Initialization
>
> 15 - An array of character type may be initialized by a character string
> literalor UTF-8 string literal, optionally enclosed in braces.
> Successive bytes of the string literal (including the terminating null
> character if there is room or if the array is of unknown size) initialize
> the elements of the array.

That appears to be the C standard, while this is a C++ group.

The languages are not the same.

C++ requires that there is room for a terminating zero.

- Alf

On Thursday, 27 July 2023 at 18:36:58 UTC+1, Alf P. Steinbach wrote:
> On 2023-07-27 4:14 PM, Tony Oliver wrote:
> > On Thursday, 27 July 2023 at 14:51:57 UTC+1, wij wrote:
> >> I found char array can be initialized by string literal ! Is such coding correct?
> >>
> >> --------------------------------------
> >> int main() {
> >> char tnam[]="tmpnamXXXXXX";
> >>
> >> int fd=::mkstemp(tnam);
> >> return 0;
> >> }
> >>
> >> g++ t.cpp -std=gnu++11
> >
> > N3096: 6.7.10 Initialization
> >
> > 15 - An array of character type may be initialized by a character string
> > literalor UTF-8 string literal, optionally enclosed in braces.
> > Successive bytes of the string literal (including the terminating null
> > character if there is room or if the array is of unknown size) initialize
> > the elements of the array.
>
> That appears to be the C standard, while this is a C++ group.
>
> The languages are not the same.
>
> C++ requires that there is room for a terminating zero.
>
>
> - Alf

Yes - I realised this wasn't in clc as soon as I posted it.
My immediate retraction request was, of course, ignored.
Apologies for any confusion caused.