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devel / comp.lang.python / Re: set.add() doesn't replace equal element

SubjectAuthor
* set.add() doesn't replace equal elementIan Pilcher
`- Re: set.add() doesn't replace equal elementStefan Ram

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set.add() doesn't replace equal element

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Subject: set.add() doesn't replace equal element
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 by: Ian Pilcher - Fri, 30 Dec 2022 21:41 UTC

I just discovered this behavior, which is problematic for my particular
use. Is there a different set API (or operator) that can be used to
add an element to a set, and replace any equal element?

If not, am I correct that I should call set.discard() before calling
set.add() to achieve the behavior that I want?

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Re: set.add() doesn't replace equal element

<set-add-20221230224443@ram.dialup.fu-berlin.de>

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From: ram@zedat.fu-berlin.de (Stefan Ram)
Newsgroups: comp.lang.python
Subject: Re: set.add() doesn't replace equal element
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 by: Stefan Ram - Fri, 30 Dec 2022 21:54 UTC

Ian Pilcher <arequipeno@gmail.com> writes:
>If not, am I correct that I should call set.discard() before calling
>set.add() to achieve the behavior that I want?

From the POV of a set, there are no "equal elements", but two
equal objects are just the same thing; so it makes no sense
to replace one by the other. You seem to want not a set but
something else. If you can get that behavior by using "set.
discard", you can use it. But that dissonance might be an early
warning that more problems with set might be waiting down
your road.

devel / comp.lang.python / Re: set.add() doesn't replace equal element

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