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devel / comp.lang.python / Object in List : how?

SubjectAuthor
* Object in List : how?Khairil Sitanggang
+* Re: Object in List : how?Dennis Lee Bieber
|`* Re: Object in List : how?Stefan Ram
| `* Re: Object in List : how?Dennis Lee Bieber
|  `- Re: Object in List : how?Khairil Sitanggang
`- Re: Object in List : how?Stefan Ram

1
Object in List : how?

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Subject: Object in List : how?
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 by: Khairil Sitanggang - Sat, 23 Jul 2022 04:28 UTC

Hello Expert:

I just started using python. Below is a simple code. I was trying to check
if, say, NO1 is not in the NODELIST[:].NO
How can I achieve this purpose?

Regards,
-Irfan

class Node:
def __init__(self):
self.NO = 0
self.A = 20

NODE = Node()
NODELIST = []

NODE.NO = 10
NODELIST.append(NODE)

NODE.NO = 20
NODELIST.append(NODE)

NODE.NO = 30
NODELIST.append(NODE)

NO1 = 20
if NO1 not in NODELIST[:].NO ???

Re: Object in List : how?

<mhnodhpl21n02qm099cvudbvomcgdo45a4@4ax.com>

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From: wlfraed@ix.netcom.com (Dennis Lee Bieber)
Newsgroups: comp.lang.python
Subject: Re: Object in List : how?
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 by: Dennis Lee Bieber - Sat, 23 Jul 2022 20:55 UTC

On Fri, 22 Jul 2022 23:28:11 -0500, Khairil Sitanggang <ksit70@gmail.com>
declaimed the following:

>class Node:
> def __init__(self):
> self.NO = 0
> self.A = 20
>
>NODE = Node()
>NODELIST = []
>

Comment...

The convention is that ALL CAPS is used to indicate something that is
to be treated as a CONSTANT. Classes get capitalized initial letters. Names
of variable data is traditionally all lower case, lower case with _ between
"words" (eg: lower_case), or camel case (eg: camelCase).

>NODE.NO = 10
>NODELIST.append(NODE)
>
>NODE.NO = 20
>NODELIST.append(NODE)
>
>NODE.NO = 30
>NODELIST.append(NODE)
>
>
>NO1 = 20
>if NO1 not in NODELIST[:].NO ???

The [:], in this statement, just says "make a copy of nodelist". The
/list/ does not have an attribute named "NO". You have to ask for each
element IN the list.

One convoluted way (I've not tested it) is:

if len([node for node in nodelist if node.no == no1]):
print("Found at least one occurence")

This is a list comprehension; it loops over each element in nodelist,
making a new list if the element attribute matches the criteria. Python
treats 0 as "false" and if no element matched, the list created is empty,
so len() is 0. Anything else implies a match was found.

--
Wulfraed Dennis Lee Bieber AF6VN
wlfraed@ix.netcom.com http://wlfraed.microdiversity.freeddns.org/

Re: Object in List : how?

<membership-20220723225235@ram.dialup.fu-berlin.de>

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From: ram@zedat.fu-berlin.de (Stefan Ram)
Newsgroups: comp.lang.python
Subject: Re: Object in List : how?
Date: 23 Jul 2022 21:54:45 GMT
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 by: Stefan Ram - Sat, 23 Jul 2022 21:54 UTC

Khairil Sitanggang <ksit70@gmail.com> writes: I was trying to check
>if, say, NO1 is not in the NODELIST[:].NO
>How can I achieve this purpose?

To check whether an object is not a member of an object,
you can use "not in".

For example, the expression

1 not in[ 1, 2, 3 ]

evaluates to "False".

Re: Object in List : how?

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 by: Stefan Ram - Sat, 23 Jul 2022 22:55 UTC

Dennis Lee Bieber <wlfraed@ix.netcom.com> writes:
> if len([node for node in nodelist if node.no == no1]):
> print("Found at least one occurence")

I'm not sure you need the "len"; an empty list already is falsy.

|>>> print( bool( [] ))
|False
|>>> print( bool( [ 1, 2, 3 ] ))
|True

Re: Object in List : how?

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 by: Dennis Lee Bieber - Sun, 24 Jul 2022 00:43 UTC

On 23 Jul 2022 22:55:47 GMT, ram@zedat.fu-berlin.de (Stefan Ram) declaimed
the following:

>Dennis Lee Bieber <wlfraed@ix.netcom.com> writes:
>> if len([node for node in nodelist if node.no == no1]):
>> print("Found at least one occurence")
>
> I'm not sure you need the "len"; an empty list already is falsy.
>

Just wanted to be explicit for the OP.

--
Wulfraed Dennis Lee Bieber AF6VN
wlfraed@ix.netcom.com http://wlfraed.microdiversity.freeddns.org/

Re: Object in List : how?

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 by: Khairil Sitanggang - Mon, 25 Jul 2022 18:29 UTC

Again, thank you so much for all your suggestions; it's even easier for me
now to proceed with my coding with all the guidance in one place (this
email thread). I highly appreciate all of your help.
I love this python community :)

Regards,
-Irfan

On Mon, Jul 25, 2022 at 12:38 PM Dennis Lee Bieber <wlfraed@ix.netcom.com>
wrote:

> On 23 Jul 2022 22:55:47 GMT, ram@zedat.fu-berlin.de (Stefan Ram) declaimed
> the following:
>
> >Dennis Lee Bieber <wlfraed@ix.netcom.com> writes:
> >> if len([node for node in nodelist if node.no == no1]):
> >> print("Found at least one occurence")
> >
> > I'm not sure you need the "len"; an empty list already is falsy.
> >
>
> Just wanted to be explicit for the OP.
>
>
> --
> Wulfraed Dennis Lee Bieber AF6VN
> wlfraed@ix.netcom.com
> http://wlfraed.microdiversity.freeddns.org/
> --
> https://mail.python.org/mailman/listinfo/python-list
>

devel / comp.lang.python / Object in List : how?

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